(x+m)(x+m)-n^2=0

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Solution for (x+m)(x+m)-n^2=0 equation: 


Simplifying
(x + m)(x + m) + -1n2 = 0

Reorder the terms:
(m + x)(x + m) + -1n2 = 0

Reorder the terms:
(m + x)(m + x) + -1n2 = 0

Multiply (m + x) * (m + x)
(m(m + x) + x(m + x)) + -1n2 = 0
((m * m + x * m) + x(m + x)) + -1n2 = 0

Reorder the terms:
((mx + m2) + x(m + x)) + -1n2 = 0
((mx + m2) + x(m + x)) + -1n2 = 0
(mx + m2 + (m * x + x * x)) + -1n2 = 0
(mx + m2 + (mx + x2)) + -1n2 = 0

Reorder the terms:
(mx + mx + m2 + x2) + -1n2 = 0

Combine like terms: mx + mx = 2mx
(2mx + m2 + x2) + -1n2 = 0

Reorder the terms:
2mx + m2 + -1n2 + x2 = 0

Solving
2mx + m2 + -1n2 + x2 = 0

Solving for variable 'm'.

The solution to this equation could not be determined.

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